-13x^2-26x=3

Solution for -13x^2-26x=3 equation:

-13x^2-26x=3

We move all terms to the left:

-13x^2-26x-(3)=0

a = -13; b = -26; c = -3;
Δ = b2-4ac
Δ = -262-4·(-13)·(-3)
Δ = 520
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{520}=\sqrt{4*130}=\sqrt{4}*\sqrt{130}=2\sqrt{130}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-26)-2\sqrt{130}}{2*-13}=\frac{26-2\sqrt{130}}{-26}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-26)+2\sqrt{130}}{2*-13}=\frac{26+2\sqrt{130}}{-26}
$